- #1
King_Silver
- 83
- 6
So I know how to do Newton's Method without any trouble, taking a value for n then taking it away from the function divided by the derivative of the function I get that entirely and have done roughly 22-23 examples of it over the past 3-4 days. However I have come across one question regarding Newton's Method and it just doesn't make sense to me at all.
It is regarding a starting value x = 0.5 and a "tolerance". No examples in my notes or maths book ever have mentioned about tolerance so I'll just ask the question here.
NOTE: Do not do it for me, that defeats the purpose of my question, I want a step-by-step explanation on how the starting value and the tolerance would be introduced to this sort of question.
Question: f(x) = (x-2)3 = 0
Find the derivative of this function, then compute the roots of this equation using Newton's method.
starting value x =0.5
vary the tolerance from 10-3 to 10-13 reducing the tolerance by 10-1 each time
It is regarding a starting value x = 0.5 and a "tolerance". No examples in my notes or maths book ever have mentioned about tolerance so I'll just ask the question here.
NOTE: Do not do it for me, that defeats the purpose of my question, I want a step-by-step explanation on how the starting value and the tolerance would be introduced to this sort of question.
Question: f(x) = (x-2)3 = 0
Find the derivative of this function, then compute the roots of this equation using Newton's method.
starting value x =0.5
vary the tolerance from 10-3 to 10-13 reducing the tolerance by 10-1 each time