Solve Work Energy Problem: Find Theta for Skier on Slope

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SUMMARY

The discussion focuses on calculating the angle (theta) of a slope for a skier sliding down a 10.2m incline with a coefficient of kinetic friction of 0.11. The skier's initial speed is 1.9m/s, and the final speed at the bottom is 8.3m/s. Participants suggest using the height of the hill to determine theta, as well as considering the horizontal distance traveled. The application of Newton's second law (F=ma) and the work-energy principle is emphasized as crucial for solving the problem.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Familiarity with the work-energy principle
  • Knowledge of trigonometric relationships in right triangles
  • Basic concepts of kinetic and potential energy
NEXT STEPS
  • Calculate the height of the hill using trigonometric functions
  • Determine the horizontal distance traveled by the skier
  • Explore the implications of kinetic friction on energy conservation
  • Review the derivation of the work-energy theorem in physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in solving real-world problems involving forces and energy on inclined planes.

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A skier slides down a slope 10.2m long, inclined at an angle (theta) to the horizontal. The coefficient of kinetic friction is 0.11. Skier's initial speed is 1.9m/s and final speed at the bottom of the slope is 8.3m/s. Find (theta), air resistance is negligible.

I have applied F=ma and Work(friction) = (delta)Kinetic Energy + (delta) Potential Energy to it and found that these two r mathematically equivallent and terms just cancel when i substitue, can any1 help me with this one?

Thx
 
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A skier slides down a slope 10.2m long, inclined at an angle (theta) to the horizontal. The coefficient of kinetic friction is 0.11. Skier's initial speed is 1.9m/s and final speed at the bottom of the slope is 8.3m/s. Find (theta), air resistance is negligible.

I have applied F=ma and Work(friction) = (delta)Kinetic Energy + (delta) Potential Energy to it and found that these two r mathematically equivallent and terms just cancel when i substitue, can any1 help me with this one?

Thx

try finding the height of the hill. you should then be able to solve for theta.

if you can find the Horizontal distance traveled, that would also be acceptable.
 
How can i find the height with only one side of the triangle known? Where solving it would involve the angle itself?
 

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