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Kinetic Energy?

 
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Oct16-11, 03:43 PM   #1
 

Kinetic Energy?


Hi, this is my first time using this forum, so i have no idea if this is even the correct place to be asking for help. I have a problem with my High School Higher Physics Homework. The question is as follow :
1. The problem statement, all variables and given/known data During one run, a car and passengers of mass 800kg are released from rest at point A, a height of 20m above the ground. The car travels a distance of 120m along the track until it reaches point C, a height of 15m above the ground. A constant frictional force of 250N acts between the car and the track as the car moves from A to C. (A diagram of the track is included, see attachments). Find the Kinetic Energy of the Car on reaching point C.


2. Relevant equations In the previous question i have been asked to calculate the work done against friction in moving from A to C, and i calculated this to be 30,000 N (W=fd W=120 * 250) (Not sure if this is correct though?) I think Ep=mgh is maybe relevent and obviously to work out the kinetic energy Ek=1/2mv^2 will be used.


3. The attempt at a solution I genuinlly have no idea where to start on this question ? I am thinking that it will maybe have something to do with Potential energy loss, and the energy lost due to friction but i am completly confuzed. Can anyone please help me ?
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Oct16-11, 04:01 PM   #2
 
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Quote by Mark Rice View Post
2. Relevant equations In the previous question i have been asked to calculate the work done against friction in moving from A to C, and i calculated this to be 30,000 N (W=fd W=120 * 250) (Not sure if this is correct though?)
Correct.
I think Ep=mgh is maybe relevent and obviously to work out the kinetic energy Ek=1/2mv^2 will be used.
Definitely.
3. The attempt at a solution I genuinlly have no idea where to start on this question ? I am thinking that it will maybe have something to do with Potential energy loss, and the energy lost due to friction but i am completly confuzed.
Think in terms of mechanical energy. You start out with some total mechanical energy at A, but you end up with less at C due to work done against friction. Set up an equation expressing this.
Oct16-11, 04:08 PM   #3
 
So would 30,000N previously worked out be the Energy 'lost to the surroundings', and also, if I am working out the kinetic energy, i assume i am not supposed to be working out the speed and using the kinetic energy equation, so how do i work it out? Sorry I'm really confuzed.
Oct16-11, 04:13 PM   #4
 
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Kinetic Energy?


Quote by Mark Rice View Post
So would 30,000N previously worked out be the Energy 'lost to the surroundings',
Yes.
and also, if I am working out the kinetic energy, i assume i am not supposed to be working out the speed and using the kinetic energy equation, so how do i work it out?
Total mechanical energy = PE + KE

So what's the total mechanical energy at point A?
Then you can figure out what it is at point C. And use that to solve for the KE at point C.
Oct16-11, 04:15 PM   #5
 
Ohhhhhhhh, thanks very much, I forgot that Total mechanical energy = PE + KE, Thanks for the help :)
Oct16-11, 04:22 PM   #6
 
Just realised i should have written down 30,000J instead of 30,000N as it is energy but that's just a units error, but once again, thanks.
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