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Simple PDE.... |
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| Oct17-11, 08:44 AM | #1 |
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Simple PDE....
I'm trying to solve the PDE:
[itex]\frac{\partial^2 f(x,t)}{\partial x^2}=\frac{\partial f(x,t)}{\partial t}[/itex] with [itex]x \in [-1,1][/itex] and boundary conditions f(1,t)=f(-1,t)=0. Thought that [itex]e^{i(kx-\omega t)}[/itex] would work, but that obviously does not fit with the boundary conditions. Has anyone an idea? |
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| Oct17-11, 08:51 AM | #2 |
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P.S. You will also need some kind of initial condition. |
| Oct17-11, 09:18 AM | #3 |
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I thought this is sufficeint data to solve it uniquely, what is the difference between boundary and initial conditions?
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| Oct17-11, 09:27 AM | #4 |
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Simple PDE.... |
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