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phase constant of SHM

 
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Oct26-11, 02:21 PM   #1
 

phase constant of SHM


1. The problem statement, all variables and given/known data

The displacement of a mass oscillating on a spring is given by x(t) = xmcos(ωt + ). If the initial displacement is zero and the initial velocity is in the negative x direction, then the phase constant is:

2. Relevant equations



3. The attempt at a solution

How do I start? The book just tells me that the phase constant depends on displacement and velocity when t = 0, but doesn't say how.
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Oct26-11, 03:28 PM   #2
 
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Sketch a cosine curve. What's its initial value? Where on the curve would match the initial condition of the spring and mass? What's (angular) the offset from zero?
Oct26-11, 04:44 PM   #3
 
Quote by gneill View Post
Sketch a cosine curve.
OK

What's its initial value?
1

Where on the curve would match the initial condition of the spring and mass?
Huh??
Oct26-11, 04:57 PM   #4
 
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phase constant of SHM


Does the mass start at a maximum extension like the cosine function does?
Oct26-11, 05:04 PM   #5
 
No, initial displacement is 0. So, I need to find where cosx equals 0?
Oct26-11, 05:13 PM   #6
 
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Quote by 1MileCrash View Post
No, initial displacement is 0. So, I need to find where cosx equals 0?
Not only that, but where it's going through zero and going negative, just like the mass' displacement.
Nov9-11, 06:19 PM   #7
 
Still have no clue on this.
Nov9-11, 07:17 PM   #8
 
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Have a gander:

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