Solving Frequencies Problem: Lowest Tone in Close-End Pipe 200Hz

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SUMMARY

The lowest tone that resonates in a closed-end pipe of length L is established at 200Hz. Frequencies that will not resonate in this pipe include 400Hz, 600Hz, 1000Hz, and 1400Hz. The fundamental frequency is calculated using the formula f1 = v/4L, where v is the speed of sound. Subsequent resonant frequencies are determined by the formula fn = (2n-1)f1, where n represents the harmonic number.

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The lowest tone to resonate in a close-end pipe of length L is 200Hz. Which is of the following frequencies will not resonate in the pipe?

400Hz
600Hz
1000Hz
1400Hz

Anyone know where I should start on this?
 
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I would start with the section in your text on pipes with closed ends.
 
This is simple, just remember for one end closed.

Fundamental Frequency:

[tex]f_{1} = \frac{v}{4l}[/tex]

The rest of the frequencies will be given by

[tex]f_{n} = (2n-1)f_{1} ... n=1,2,3...[/tex]
 

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