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diracdelta
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Homework Statement
Open and closed pipe, give 5 beats per second.
Open pipe is 30 cm long and gives a tone of frequency f0.
Speed of sound is 330 m/s.
How long do we need to extend closed pipe so both pipes give equal frequencies?
Homework Equations
Open pipe, fn=n*f1, f1=v/(2L)
Closed pipe; fn= f*f1, f1 = v/(4L)
fbeat = f2 - f1
The Attempt at a Solution
For open pipe, I assume that f0 is f1, or basic frequency.
f=v/2L=330 ms-1 / 0,6 m = 550 Hz
fbeat = f2 - f1
5 = f2 - 550 Hz
f2 = 555 Hz.
Now we need to find the length of open pipe.
4L = v/f2
l= v/4f2= 0,15 m
Since i have the length of closed pipe, motive is to adjust it so we have frequency of 550 Hz.
4L = v/f2,
4*L = 330 ms-1/ 550 Hz
4*L = 0,6 m
L = 0,15
What did I do wrong?