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Working out the units? 
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#1
Nov811, 05:38 PM

P: 10

I am having a problem finding the correct SI unitsfor the quantity A?
In the equation A=√(R/TY) That is A equals the square root of R divided by TY (not to good showing workings on the computer sorry) , the SI units of the quantity R are kg m^3 s^–2, the SI units of the quantity T are kg and the SI units of the quantity Y are m s^–2. What are the correct SI units for the quantity A? 


#2
Nov811, 06:29 PM

Mentor
P: 21,215

Is the expression on the right side this? [tex]\sqrt{\frac{R}{TY}}[/tex] or this? [tex]\frac{\sqrt{R}}{TY}[/tex] 


#3
Nov811, 06:32 PM

P: 10

The first one R/ty all square root. Do apologise for the bad format



#4
Nov811, 07:57 PM

P: 873

Working out the units?
Then, the units of A are meters.



#5
Nov911, 12:47 PM

P: 754

To clarify gsal's answer...
You have the expression [tex]\sqrt{\frac{R}{TY}}[/tex] Simply, insert the units for each variable (in place of the variables): [tex]\sqrt{\frac{\frac{kg\cdot m^3}{s^2}}{(kg)(\frac{m}{s^2})}}[/tex] and simplify... [tex]\sqrt{\left(\frac{kg \cdot m^3}{s^2}\right) \left(\frac{s^2}{kg \cdot m}\right)}[/tex] kg and s^{2} cancel out, leaving [tex]\sqrt{\frac{m^3}{m}}[/tex] which is [tex]\sqrt{m^2}[/tex] or, more simply m 


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