SHM with mass over pulley problem

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Homework Help Overview

The discussion revolves around a problem involving simple harmonic motion (SHM) with a mass attached to a spring and a pulley system. The original poster seeks to determine the frequency of oscillation for two scenarios: one with a negligible mass pulley and another with a pulley mass of 0.25 kg.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of formulas related to SHM, including the tension formula and the moment of inertia of the pulley. Questions arise regarding the influence of gravity on the system's equilibrium and frequency.

Discussion Status

Participants are exploring different aspects of the problem, including the effects of gravity on the mass and the relationship between the spring's elongation and the pulley. Some guidance has been offered regarding the use of specific formulas, but there is no explicit consensus on the implications of gravity in the context of frequency calculation.

Contextual Notes

There is an assumption that the spring is at equilibrium when the mass is released, and participants are considering the implications of the mass of the pulley on the overall dynamics of the system.

gaborfk
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I am having a problem with this:

One end of a light spring with force constant 100N/m is attached to a vertical wall. A light string is tied to the other end of the horizontal spring. The string changes from horizontal to vertical as it passes over a solid pulley of diameter 0.04m. The pulley is free to turn on a fixed smooth axle. The vertical section of the string supports a 0.2kg mass. The string does not slip at its contact with the pulley. Find the frequency of oscillation of the object if the mass of the pulley is

a) negligible

b) 0.25kg


Thank you in advance.
 
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For the part a), you can just apply the formula [tex]T=2\pi\sqrt{\frac{m}{k}}[/tex].
For part b), you have to calculate the moment of inertia of the pulley. Then apply formula [tex]\tau=I\alpha[/tex]. You also need to find out the total elongation of the spring first by assuming that the mass is being let go when the spring is at equilibrium. Since the string does not slip at its contact with the pulley, this elongation will tell you something on the pulley.
 
On part a)

I would not have to consider that the mass is hanging, by including gravity somehow?
 
gaborfk said:
On part a)

I would not have to consider that the mass is hanging, by including gravity somehow?
The fact that the mass is hanging will affect the equilibrium position, but not the frequency.

One way to solve this problem is to write the equation of motion of the system and compare it to the basic dynamical equation for simple harmonic motion of a mass on a spring:
[tex]\frac{d^2x}{dt^2} = \frac{k}{m} x[/tex]
 
If you know how to derive that formula. You will know that it's not affected by gravity.
 

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