Spring mass pulley system frequency equation

In summary: The theoretical natural frequency would be greater if the system had more mass in the pulley, or if the system had a longer string.
  • #1
Name15
30
1

Homework Statement


A spring is attached to the ceiling, a pulley is attached to the other end of the spring, a string is suspended over the pulley, and a mass attached to the free end of this string. The system oscillates vertically.

Can someone PLEASE help me derive this equation for natural frequency:

f = (1/2pi) * SQRT(k / (m + m(s)/3))

where f = frequency
k= spring constant
m = mass attached to a spring
m(s) = mass of spring

Homework Equations


F=ma=-kx
mx''+kx=0
(Wn)^2 =k/m

The Attempt at a Solution


mx''=-kx
x''=-wn^2.x
 
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  • #2
Can you provide a diagram. Your description doesn't make sense if the string is not somehow anchored on the other end.

Chet
 
  • #3
SHM_Dia_30.gif


sorry, i should have mentioned, the string is attached to say a table.
 
  • #4
Are you supposed to be considering the case where the spring has mass, or are you allowed to assume that the spring is massless? Is the pulley supposed to have mass?

I suggest that you solve this problem first for the case of a massless spring and pulley. Why? Because if you can't solve it for that case, then you'll never be able to do it for more complicated cases. Plus, when you complete that solution, you will have something to show for it, and will have developed the general technique for attacking the problem.

Have you considered drawing free body diagrams on the spring and mass, and identifying the forces acting on each? Have you written down force balance equations for the spring and mass?

Chet
 
  • #5
i have tried many different approaches, from equation of motion to energy conservation methods, only to have been unsuccessful.

The spring and pulley masses are considered in the above. The string is massless.
 
  • #6
Name15 said:
i have tried many different approaches, from equation of motion to energy conservation methods, only to have been unsuccessful.

The spring and pulley masses are considered in the above. The string is massless.
Well, you have to go back to basics. Can you at least determine the tensions in the string and spring if the system is in static equilibrium, without any oscillation? That would be your starting point for the dynamic analysis.

Chet
 
  • #7
for system without mass: 2T=kx
when mass is isolated: T=mg
 
  • #8
<< Mentor Note -- 2 threads merged >>

In an experiment to determine the natural frequency of a spring-mass-pulley system, why would the experimental natural frequency (found using 1/time) be greater than the theoretical natural frequency found using the following:

f=1/2pi∗sqrt(k/4m+ms/3)Anything other than the pulley mass and rope mass being neglected.

Also, should the experimental f be greater?
 
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Related to Spring mass pulley system frequency equation

What is a spring mass pulley system frequency equation?

A spring mass pulley system frequency equation is a mathematical formula that describes the frequency of oscillations in a system consisting of a mass attached to a spring and a pulley. It takes into account the mass of the object, the stiffness of the spring, and the geometry of the pulley.

What factors affect the frequency of a spring mass pulley system?

The frequency of a spring mass pulley system is affected by three main factors: the mass of the object, the stiffness of the spring, and the geometry of the pulley. A heavier mass will result in a lower frequency, while a stiffer spring and a larger pulley will result in a higher frequency.

How is the frequency of a spring mass pulley system calculated?

The frequency of a spring mass pulley system can be calculated using the following formula: f = (1/2π) * √(k/m), where f is the frequency in Hertz, k is the spring constant in Newtons per meter, and m is the mass in kilograms.

What is the significance of the frequency in a spring mass pulley system?

The frequency in a spring mass pulley system determines how quickly the system will oscillate or vibrate. A higher frequency means that the system will oscillate more quickly, while a lower frequency means that the oscillations will be slower.

How does the frequency of a spring mass pulley system affect its behavior?

The frequency of a spring mass pulley system is directly related to its period, which is the time it takes for one complete oscillation. A higher frequency results in a shorter period, meaning that the system will complete more oscillations in a given amount of time. This frequency also determines the amplitude of the oscillations, with a higher frequency resulting in larger amplitudes.

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