Efficient Air Duct Design for 121m^3 Room | Air Conditioning System Calculation

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Homework Help Overview

The discussion revolves around the design of an air duct system for a room with a volume of 121m³, focusing on calculating the dimensions of ducts required to replace the air in the room every thirty minutes at a specified air speed.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses confusion about how to begin the problem. One participant suggests converting the time frame into seconds and calculating the flow rate of air to determine the duct area based on the relationship between flow, speed, and area.

Discussion Status

Participants are actively engaging with the problem, with one providing a potential approach to calculate the necessary parameters. There is an indication of supportive interaction, but no consensus or resolution has been reached.

Contextual Notes

The problem assumes air behaves as an incompressible fluid and involves specific constraints related to the volume of the room and the air speed within the ducts.

SnowOwl18
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----A room has a volume of 121m^3. An air-conditioning system is to replace the air in this room every thirty minutes, using ducts that have a square cross section. Assuming that air can be treated as an incompressible fluid, find the length of a side of the square if the air speed within the ducts is 2.86m/s.----

Um...I'm lost on this one. Not sure where to start...any help would be much appreciated. :)
 
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SnowOwl18 said:
----A room has a volume of 121m^3. An air-conditioning system is to replace the air in this room every thirty minutes, using ducts that have a square cross section. Assuming that air can be treated as an incompressible fluid, find the length of a side of the square if the air speed within the ducts is 2.86m/s.----

Um...I'm lost on this one. Not sure where to start...any help would be much appreciated. :)

First of all,u need to transform the time given (30 mins) into seconds.The result is,obviously,1800 secs.Since all the air in is evacuated within this time,calculate the flow (how many cubic meters of air is taken out in one second).Once u got the flow,the area is simple to determine,since the flow is intimately linked with the speed and the surface.Actually it's the product of the 2.You have the flow,the speed,so the area is easy to calculate.

Good luck!

Daniel.
 
oo thank you so much! you rock :D
 
SnowOwl18 said:
oo thank you so much! you rock :D

You're welcome! :blushing:
 

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