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Solve an equation with complex numbers

 
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Dec7-11, 01:41 PM   #1
 

Solve an equation with complex numbers


1. The problem statement, all variables and given/known data
I am doing a problem where I have to design a controller for a system. I have to solve the below equation for ω

3.1 (ω)^2 - 6.2iω - 20

2. Relevant equations



3. The attempt at a solution

I am not sure how to start It looks like a quadratic but I don't know what to do with the i
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
 
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Dec7-11, 01:53 PM   #2
 
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Looks like a quadratic, quacks like a quadratic. It is probably quadratic. You can use all the normal methods to solve it. The i is just part of the coefficient of the linear term.
 
Dec7-11, 02:31 PM   #3
 
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I can't really see an equation anywhere. All I see is an expression in [itex]\omega[/itex]. An equation must contain an "=".
 
Dec7-11, 02:37 PM   #4
 
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Solve an equation with complex numbers


Yes, that's a quadratic. What it isn't is an equation! What is the problem really? Do you know the quadratic formula?
 
Dec7-11, 02:46 PM   #5
 
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Sorry, I thought he meant to factor it. Good point!
 
Dec7-11, 04:34 PM   #6
 
Ok, it's the "i" that's causing the problem for him. That's intimidating to a lot of students not familiar with complex variables.

The think to do 2slow is not be intimidated by them. Treat them just like constants but remember the complex arithmetic i times i is minus one. So you have:

[tex]w^2-6.2iw-20=0[/tex]

(I heard a quack)

alright, that 6.2i is just a constant. Treat it just like if you were solving:

[tex]w^2-aw-20=0[/tex]

as long as you remember to do the complex arithmetic with i's so:

[tex]w=\frac{6.2i\pm\sqrt{(6.2i)^2+80}}{2}[/tex]

Not gonna' have problems with that (6.2i)^2 thing right?
 
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