Solving Arithmetic and Series Problems in IB Math Methods

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Homework Help Overview

The discussion revolves around problems related to arithmetic sequences and series, specifically within the context of IB Math Methods. Participants are exploring the properties of an arithmetic sequence with a common difference and a specified sum, as well as the evaluation of a series defined by a linear expression.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conditions of the arithmetic sequence, including the relationship between the first term and the number of terms. There is an attempt to derive the sum of the series and clarify the nature of the last term. Questions arise regarding the validity of negative values for the number of terms and the implications of the series being finite versus infinite.

Discussion Status

Some participants have provided insights into the mathematical formulation of the problems, while others express confusion about specific aspects, such as the relevance of negative terms and the interpretation of the series. There is an ongoing exploration of the correct approach to defining the series and its sum.

Contextual Notes

Participants are navigating the constraints of the problem, including the requirement that the first term must be a positive integer and the implications of the series being finite. There is also mention of multiple-choice options for one of the questions, which may influence the discussion.

Astronomer107
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I've been working on these problems for a long time trying to prove to myself that I'm not stupid (though I am convinced I am because I don't feel like "IB material" at the moment), but this will be impossible since I have other things to do. So, my two questions are these:

1. An arithmetic sequence has a common difference of 2 and a sum of 120. The first term is numerically equal to the number of terms. FInd all possible values of hte first.

I know that the answer is 8 because it is a multiple choice question and through elimination, the others aren't possible, but I don't understand how to prove this mathematically.

2. Determine Sn of the series 4 + 10 + 16 + 22+...+ (6n - 2).

I tried to solve this one, but when I did, the n's canceled out, making it "all real numbers" and since (6n - 2) is the last term, the series isn't infinite.

PLEASE HELP ME! Thanks!
 
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1) The series is: [sum] [ x + 2*y] from y = 0 to x-1

To solve an arithmetic series it is 1/2 times the size of the series times the quantity of the first term plus the second

Sn = (1/2) * n * ( a1 + a2 )

the first term you know is the number of terms in the series and the last term is equal to n+2*(n-1) based on the equation.

So..

Sn = (1/2) * n * ( n + [ n + 2*(n-1) ] )

Then you solve Sn = 120

And you get n = 8 and -7.5

2) I'm unsure what your asking

the series is
[sum] 6x-2 from x=1 to ?

your saying the series isn't infinite, so what is it?

if the series goes from x=1 to infinity then the series diverges
 
Originally posted by dduardo


Then you solve Sn = 120

And you get n = 8 and -7.5

2) I'm unsure what your asking

the series is
[sum] 6x-2 from x=1 to ?

your saying the series isn't infinite, so what is it?

if the series goes from x=1 to infinity then the series diverges

Thanks for the help on the first question. I was assuming the series was finite because (6x - 2) is the last term in the series. Another question: I don't understand how -7.5 can be relevant because it says that n is equal to the number of terms, but there can't be -7.5 terms... can there?
 
I think that what the question for is the sum as a function of n.

Sn = F(n)

What you would do is write out the summation, and then use the rules that you know to reduce it into a formula.

For example:

[sum]c from i=0 to n = cn (c is a constant
[sum]i from i=0 to n = 1/2(i+1)*i
 
Astronomer107: -7.5 can occur in a quasi-hyperdimesion manifold, that is forumalated by using the...

No, you are right, -7.5 isn't an answer. (Only in my imagination)

Also, what are the choices for question 2.

Is there an answer: n*(3*n+1)
 

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