Why Does a Bubble Expand as It Rises to the Surface?

  • Thread starter Thread starter Mo
  • Start date Start date
  • Tags Tags
    Pressure Volume
Click For Summary
SUMMARY

The discussion centers on the physics of a bubble's expansion as it rises in water, specifically addressing the relationship between pressure and volume as described by Boyle's Law (P1V1 = P2V2). The bubble's volume increases from 4mm³ to 20mm³ due to a decrease in pressure as it ascends, while the water temperature remains constant. The atmospheric pressure at the lake's surface is equivalent to an additional 10m of water, which is crucial for calculating the lake's depth based on the pressure difference between the surface and the bottom.

PREREQUISITES
  • Understanding of Boyle's Law (P1V1 = P2V2)
  • Basic principles of fluid mechanics
  • Knowledge of atmospheric pressure and its effects on gases
  • Concept of hydrostatic pressure in fluids
NEXT STEPS
  • Study Boyle's Law in detail and its applications in real-world scenarios
  • Learn about hydrostatic pressure calculations in fluid mechanics
  • Explore the relationship between temperature and pressure in gases
  • Investigate the behavior of gases under varying pressure conditions
USEFUL FOR

Students studying physics, educators teaching fluid mechanics, and anyone interested in understanding the behavior of gases in liquids.

Mo
Messages
81
Reaction score
0
I have attempted the first part of this question.I am hoping someone will be able to check if they think my reasoning is ok.The second part however, has me stumped A push in the right direction would be quite nice --thank you!--

The Question
"A fish resting on the bottom of a lake releases a small air bubble from its mouth.The bubble increases in volume as it journeys to the surface through water known to be at a constan temperature.Explain why the volume of the bubble increases as it rises to the surface.The volume of the realeased bubble was 4mm^3 but had increased to 20mm^3 (cubed) by the time it had reached the surface.Given that the atmosphjeric pressure acting on the surface of the lake is equivalent to an additional 10m of water, calculate the depth of the lake at the point where the fish is resting.Explain all your working.

My Answer
a) "The volume of the bubble increases as it rises to the surface, this can be because of:

The pressure being decreased
The temperature decreasing

Since both are related to each other, we can only assume that the temperature of the bubble decreased (to that of the sea level constan), wghich led to a a decrease in pressure and hence, an increase in volume"

b) Have not got a clue.

I hope someone will be able to check my first answer, and maybe give me a little push in the right direction for part b. Thanks very much,

Regards,
Mo
 
Physics news on Phys.org
My Answer
a) "The volume of the bubble increases as it rises to the surface, this can be because of:

The pressure being decreased
The temperature decreasing

Since both are related to each other, we can only assume that the temperature of the bubble decreased (to that of the sea level constan), wghich led to a a decrease in pressure and hence, an increase in volume"

It is given that the temparature of the water remains constant. So
[tex]P*V = Constant[/tex]

As one moves up from the bottom of the lake, there is a drop of pressure.
P decreased means V should increase.

For the second part, if what is given as the additional pressure (10 m water) is the pressure difference between lake bottom and the surface, then the answer is very straight forward.

Gamma.
 
As Gamma explained, treat the temperature of the water as constant throughout, so:
[tex]P*V = Constant[/tex]

For part 2, you need to figure out the pressure difference between the surface and bottom of the lake. Use the given bubble volumes and the pressure at the surface (= 10 m of water!) to solve for the pressure at the bottom. Set up a ratio like this: [itex]P_1 V_1 = P_2 V_2[/itex].
 
Fish are cold blooded. There would be no reason for the initial temperture of the bubble to be different from the temperature of the water which we are told is a constant.

The pressure on the bubble is equal to the atmospheric pressure plus the weight of water above (which decreases as it rises) divided by the surface area of the bubble.
 
Thank you for your help, all. It has helped me realize the answer (and the fact i got to revise this stuff a lot more!)

Reagrds,
Mo
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
1
Views
2K
Replies
1
Views
7K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
5
Views
5K
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K