When will the walking boy reach school?

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  • Thread starter Thread starter courtrigrad
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SUMMARY

The discussion centers on a mathematical problem involving a cyclist and a walking boy, where the cyclist travels at c miles per hour and the walker at w miles per hour. The cyclist reaches school 10 minutes before the walker, leading to the conclusion that the walker arrives 10(c/w - 1) minutes after the cyclist. The expression can be simplified to 10(c - w)/w, highlighting the relationship between their speeds and the time difference in their arrivals.

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A boy cycling to school at c miles per hour passes a boy walking there at w miles per hour. 10 minutes later, the cyclist reaches school. How many minutes after that does the other boy reach school?

I know d= 10c.

The difference in their speeds is c - w. I would I find the amount of time after the other boy reaches school?

Thanks
 
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we have distance = 10c
So time taken by the boy who is walking = 10c/w minutes
S0 the person walking will reach school 10c/w-10 minutes after the cyclist .
One interesting thing is the expression can be re wirtten as 10(c-w)/w. 10(c-w) being the relative distance and w being the velocity ...

regards
Mahesh
 
thanks a lot mahesh
 

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