How to Solve Distance Word Problems Involving Two Professors and Two Cyclists?

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  • Thread starter paulmdrdo1
  • Start date
In summary, word problems involving distance require calculating the distance between two objects or the time it takes for an object to travel a certain distance. To solve these problems, you must identify the given information and use the appropriate formula to set up and solve an equation. Common units used in these problems include miles, kilometers, meters, feet, and inches, and a calculator can be used to solve them as long as the correct formula is used and the numbers are entered correctly. These types of problems have real-life applications in various fields and can help develop critical thinking and problem-solving skills.
  • #1
paulmdrdo1
385
0
1. Professors Roberts and james, who live 676 miles apart,
are exchanging houses and jobs for four months. They
start out for their new locations at exactly the same
time, and they meet after 6.5 hours of driving. If their
average speeds differ by 4 miles per hour, what is each
professor’s average speed?

my work is

let $x=$ prof Robert's speed.
$x+4=$ prof. James' speed.

since the took 6.5 hours to meet each other,

i have

$6.5x+6.5(x+4)=676$

$x=50$

$50$ mph - prof Robert's speed
$54$ mph - prof James' speed.

am I correct?

2. Two cyclists start out at the same time from points
that are 395 kilometers apart and travel toward each
other. The first cyclist travels at an average speed of
40 kilometers per hour, and the second travels at an
average speed of 50 kilometers per hour. After how
many hours will they be 35 kilometers apart?

i don't know where to start here.
 
Last edited:
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  • #2
Re: word problems(distance)

paulmdrdo said:
$50$ mph - prof Robert's speed
$54$ mph - prof James' speed.

am I correct?
Yes, except the problem does not say which if the two was going slower.

paulmdrdo said:
2. Two cyclists start out at the same time from points
that are 395 kilometers apart and travel toward each
other. The first cyclist travels at an average speed of
40 kilometers per hour, and the second travels at an
average speed of 50 kilometers per hour. After how
many hours will they be 35 kilometers apart?

i don't know where to start here.
How is this harder than problem 1? You know the total distance traveled (395 - 35 = 360km), and you know the speed of each cyclist.
 
  • #3
Re: word problems(distance)

paulmdrdo said:
2. Two cyclists start out at the same time from points
that are 395 kilometers apart and travel toward each
other. The first cyclist travels at an average speed of
40 kilometers per hour, and the second travels at an
average speed of 50 kilometers per hour. After how
many hours will they be 35 kilometers apart?

i don't know where to start here.

Hello.

I recommend to you that, always, in this style of questions, you realizes a table. I believe that you will understand it better.

speeddistancetime
Total[tex]395-35[/tex]
The firts40dt
The second50[tex]360-d[/tex]t

You look, if you can continue.

Regards.
 
  • #4
Re: Word problems(distance)

i don't know if this is correct

my solution.

let $t=$ time it takes for the two cyclists to be 35km apart.

$50t+40t=360$

$90t=360$ then $t=4$

so after 4 hours the two cyclist will be 35 km apart. am I correct?
 
  • #5
Re: Word problems(distance)

Yes, this is correct.
 
  • #6
Re: Word problems(distance)

Hello.

Yes, it is correct.

Regards.

Edit.

I am sorry, Evgeny. I have seen your respuest later.:mad:
 
  • #7
Re: Word problems(distance)

paulmdrdo said:
2. Two cyclists start out at the same time from points
that are 395 kilometers apart and travel toward each
other. The first cyclist travels at an average speed of
40 kilometers per hour, and the second travels at an
average speed of 50 kilometers per hour. After how
many hours will they be 35 kilometers apart?

i don't know where to start here.
They are moving toward each other with a relative speed of 50+ 40= 90 kilometers per hour. Since they were initially 395 kilometers apart, when they are 35 kilometers apart, they must have covered 395- 35= 360 kilometers. It will take 4 hours to cover 360 kilometers at 90 kilometers per hour.
 

Related to How to Solve Distance Word Problems Involving Two Professors and Two Cyclists?

What are word problems involving distance?

Word problems involving distance typically involve calculating the distance between two objects or the time it takes for an object to travel a certain distance.

How do I solve word problems involving distance?

To solve a word problem involving distance, you will need to first identify the given information and what is being asked. Then, use the appropriate formula (such as d=rt for distance, rate, and time problems) to set up and solve an equation.

What are some common units used in distance word problems?

Some common units used in distance word problems include miles, kilometers, meters, feet, and inches. It is important to pay attention to the units given in the problem and convert if necessary to ensure accurate calculations.

Can I use a calculator to solve distance word problems?

Yes, you can use a calculator to solve distance word problems. However, it is important to make sure you are using the correct formula and entering the numbers correctly to get an accurate solution.

What are some real-life applications of distance word problems?

Distance word problems are commonly used in various fields such as physics, engineering, and transportation. For example, calculating the distance between two cities for a road trip or determining the speed of a moving object. These problems also help develop critical thinking and problem-solving skills.

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