Calculating Ksp of Thallium Chloride at 100 Degrees Celsius

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SUMMARY

The discussion focuses on calculating the solubility product constant (Ksp) of Thallium(I) Chloride (TlCl) at 100 degrees Celsius, given a saturated solution concentration of 2.4 g per 100 mL. The molar concentration of the chloride ion (Cl-) is determined to be 0.677 mol/L. The Ksp expression for Thallium(I) Chloride is established as Ksp = [Tl1+][Cl1-], indicating that the molar concentrations of Tl+ and Cl- are equal due to the 1:1 stoichiometry of the dissociation reaction.

PREREQUISITES
  • Understanding of solubility product constant (Ksp)
  • Basic knowledge of molarity and concentration calculations
  • Familiarity with chemical formulas and stoichiometry
  • Ability to perform unit conversions (grams to moles)
NEXT STEPS
  • Calculate Ksp for Thallium(I) Chloride using the derived concentrations
  • Explore the concept of solubility equilibria in ionic compounds
  • Learn about the impact of temperature on solubility and Ksp values
  • Investigate the dissociation reactions of other salts to compare Ksp values
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Chemistry students, educators, and professionals involved in analytical chemistry or materials science who are interested in solubility and equilibrium concepts.

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I am having a tough time with getting my heard around what Ksp is; this question isbugging the heck out of me:

Q:
Calculate the Ksp of Thallium(1) Chloride at 100 Degrease celsius. The concentration of saturated solution of salt at this temperature is 2.4g / 100 ml .

Me:
As far as i got...

The Ksp of Thallium = [TI][Cl]

and

2.4 g / 100 ml is 0.677 mol / L of Cl ?


But beyond that I don't understand what i should be doing...
 
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Ksp = [Tl1+][Cl1-], which you wrote correctly.

So what is the molar concentration of each species? Tl and Cl must have the same concentration, and one mole of TlCl, yields one mole of each species.
 

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