| New Reply |
Homogeneous now seperable ODE |
Share Thread | Thread Tools |
| Mar3-12, 09:13 AM | #1 |
|
|
Homogeneous now seperable ODE
[Ok so I have transformed a
1st order homogenous ODE into a seperable ODE. However I am having trouble seperating to get y on it's own. Here's the problem: du/dx=(2u^2)/x where u = y/x du/(2u^2)=dx/x <<can't get tex to work -1/(4u^2)=ln(x)+C=ln(Ax) <<can't get tex to work 1=-4u^2ln(Ax) 1=-4(y^2/x^2)ln(Ax) y^2=-4x^2ln(Ax) y=i2xsqrt(lnAx) Is this algebra correct? Is this the right solution? I'm not sure about bringing the y^2 over to the left is ok. |
| Mar3-12, 10:19 AM | #2 |
|
|
I realise now, I messed up the integration.
The general solution is: y=-x/(ln(Ax^2)) |
| New Reply |
| Tags |
| algebra, homogeneous, ode, seperable |
| Thread Tools | |
Similar Threads for: Homogeneous now seperable ODE
|
||||
| Thread | Forum | Replies | ||
| Seperable DE | Differential Equations | 2 | ||
| ode seperable eq. | Calculus & Beyond Homework | 6 | ||
| Non-Seperable ODE Help | Differential Equations | 11 | ||
| If you have the seperable DE.... | Introductory Physics Homework | 1 | ||