## question regarding empirical formula and molecular formula(finding 2 variables)A Lvel

1. The problem statement, all variables and given/known data

http://www.xtremepapers.com/CIE/Inte..._s11_qp_12.pdf

question 10

2. Relevant equations

3. The attempt at a solution
The way I am doing it, is to get two equations in terms of x and y and then equate them. For the first equation I used the fact that all of the element's individual atomic masses will add up to 571.5. So i got 27x + 28.1y = 172
My problem now is how to get the second equation? I think it has something to do with the empirical formula, but I can't figure it out. Help!

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 If you remove the Al and Si from the formula, what is the charge on the resulting ion?
 Admin What is 14.04% of 571.5?

## question regarding empirical formula and molecular formula(finding 2 variables)A Lvel

 Quote by Borek What is 14.04% of 571.5?
I think I got it, thanks to you. So for x we find 14.17% of 571.5. That answer we divide by 27, (because we know that the mole of aluminium is 1), and the x i got is 2.999(pretty close to one of the options). Same for y. Thanks!