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Deviation by a thin prism

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shr
#1
Mar13-12, 08:52 PM
P: 2
1. The problem statement, all variables and given/known data
This really is not a Homework question, but I guess it fits in here. So, according to snell's law the ratio of sine of angle of incidence to the sine of angle of refraction is a constant called refractive index. But, in our textbook while deriving an expression for "Deviation by a thin prism", Snell's law seems to be used incorrectly. They have written "n = sin (refracted)/sin (incident)", which I do not understand, until now. Probably I'm wrong because I'm just a learner. Do you guys have any idea?


2. Relevant equations
A scan of the derivation, from our textbook:



3. The attempt at a solution
I googled, but did not find anything interesting.
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rl.bhat
#2
Mar14-12, 05:37 AM
HW Helper
P: 4,439
General expression for Snell's law is
n1*sini1 = n2*sini2 where 1 suffices indicates the incident medium and suffices 2 indicates refracted medium.
Now apply the law to the face AC of the thin prism ABC.
shr
#3
Mar14-12, 08:20 AM
P: 2
Quote Quote by rl.bhat View Post
General expression for Snell's law is
n1*sini1 = n2*sini2 where 1 suffices indicates the incident medium and suffices 2 indicates refracted medium.
Now apply the law to the face AC of the thin prism ABC.
RL, I figured it out myself after asking the problem:)

The root of the problem arose from our text book. They had, at first defined refractive index as "sin i/sin r" but did not mention that it only holds good in the case where a light ray falls from air(n = 1) into another medium. That's where I fell :)

Thanks for your reply.


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