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integration and differentiation |
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| Mar18-12, 06:05 AM | #1 |
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integration and differentiation
Why is antiderivative and area under the curve the same thing? Its not at all intuitive to me
Derivative is the slope at a point and its opposite is area?? Can someone just explain me why when we are finding an antiderivative, we are actually finding area under the curve i dont buy the fact that slope of a curve and area under the curve ae opposite of each other |
| Mar18-12, 06:23 AM | #2 |
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Oh my! Right now you're undergoing your very first mathematical crisis! I've been there some years ago and trust me, eventually you will understand it.
I recommend you read a book by William Dunham, "The mathematical universe" chapters D, K and L. It's something you must discover by your own. For now I can just say that you are confusing "antiderivative" with "integral", which are quite different things. The first is a function, while the later is a real number. |
| Mar18-12, 07:57 AM | #3 |
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The standard proof is this- look at the graph of y= f(x), a continuous. Let the area under the curve, above y= 0, and between x= a and x, be F(x). Let [itex]x^*[/itex] be a value x at which F takes its maximum, [itex]x_*[/itex] a value at which F takes its minimum on [a, x]. Then we must have [itex]f(x_*)(x- a)\le F(x)\le f(x^*)(x- a)[/itex]. Then
[tex]\frac{F(x_*)}{x- a}\le f(x)\le\frac{F(x^*)}{x- a}[/tex] Because both x* and [itex]x_*[/itex] are between a and x, if we take the limit as x goes to a, x* and [itex]x_*[/itex] will also both go to a. But then, [tex]\lim_{x\to a}\frac{F(x_*)}{x-a}= \lim_{x\to a}\frac{F(x^*)}{x- a}= \frac{dF}{dx}[/tex] and we have [tex]\frac{dF}{dx}\le f(x)\le \frac{dF}{dx}[/tex] |
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