Exploring the Shell Model of Nucleus: An Introduction to Nuclear Physics

In summary, B.R. Martins' book, "An Introduction to Nuclear and Particle Physics," discusses the shell model of the nucleus and its analogy to the periodic table. Martin notes that for atoms with a closed shell or subshell, the electrons are paired off and therefore chemically inert. The atomic numbers at which this occurs can be calculated, but it is not an easy task. The strong interaction in a nucleus is different from that of the hydrogen atom, resulting in a complex energy level pattern with different magic numbers.
  • #1
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I'm currently reading about nuclear and particle physics in B.R.Martins 'An introduction to nuclear and particle physics'.

In chapter 7.3 he introduces the shell model of the nucleus and draws an analogy to the periodic table and how we think of it being constructed of progressively placing more and more electrons in 'orbitals' given by the quantum numbers n,l and ml.

From the study of the hydrogen atom we know that the energy levels are degenerate with 2n^2. Martin further notes that if a shell or a subshell is filled then

[tex]\sum m_s = \sum m_l = 0[/tex]
which implies that
[tex]\vec L = \vec S = 0 = \vec J = \vec L + \vec S.[/tex]
He then states that 'For any atom with a closed shell or a closed sub-shell, the electrons are paired off and thus no valence electrons are avaiable. Such atoms are therefore chemically inert. It is straight forward to work out the atomic numbers at which this occurs. These are

[tex]Z = 2,10,18,36,54.[/tex]'

But I do not understand how these numbers are obtained. If one follows the 'hydrogen model' I would think that the numbers at which we have a closed shell or subshell would be

[tex] Z = 2,4,10,12,18,28, \ldots[/tex]

corresponding to the electron configurations

[tex] 1s^2, 1s^2 2s^2, 1s^2 2s^2 2p^6,1s^2 2s^2 2p^63s^2, \ldots[/tex]

What have I missunderstood here?
 
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  • #2
The strong interaction in a nucleus is a bit different from the hydrogen atom. There, electrons have a potential given by other particles (the nucleus), with an 1/r^2-law. This is not true for the strong interaction, where the interaction is short-ranged and given by other nucleons in the same volume. As a result, the energy levels depend heavily on the quantum states, and you get a nice mess with different magic numbers.
 
  • #3
But how, then, can it be that

It is straight forward to work out the atomic numbers at which this occurs
?
Can these be calculated within a theoretical framework?
 
  • #4
You can work out these numbers if you know the energy levels.
Calculating these energy levels (numerically) is not so easy, but it is possible.
 

1. What are atomic 'magic' numbers?

Atomic 'magic' numbers refer to specific numbers of protons or neutrons in the atomic nucleus that result in increased stability and lower energy levels.

2. How are atomic 'magic' numbers determined?

Atomic 'magic' numbers are determined through experimental observation and theoretical calculations. Scientists have found that certain numbers of protons and neutrons, such as 2, 8, 20, 28, 50, and 82, tend to result in more stable nuclei.

3. Why are atomic 'magic' numbers important?

Atomic 'magic' numbers are important because they provide a better understanding of nuclear structure and help to explain the properties and behavior of atoms. These numbers also play a role in nuclear reactions and the stability of isotopes.

4. Are atomic 'magic' numbers the same for all elements?

No, atomic 'magic' numbers are not the same for all elements. The numbers may vary depending on the element's atomic number and the arrangement of protons and neutrons in the nucleus.

5. Can atomic 'magic' numbers change?

Yes, atomic 'magic' numbers can change with advancements in technology and scientific understanding. As we continue to study and explore the properties of atoms, we may discover new 'magic' numbers or refine our understanding of existing ones.

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