| New Reply |
Linear Algebra- Finding the intersection of two straight lines. |
Share Thread |
| May6-12, 04:47 PM | #1 |
|
|
Linear Algebra- Finding the intersection of two straight lines.
1. The problem statement, all variables and given/known data
Determine whether the following two lines intersect: (x-2)/2 = (y+3)/1 = (z-4)/-3 ,and (x+3)/4 = (y+4)/1 = (-z+8)/4 Find an intersection point, then find the distance between the lines. 2. Relevant equations Symmetric equations of a straight line (given) Parametric equations of a straight line. AxB/mag(AxB) 3. The attempt at a solution First I parametrized the equations and got : x=1+2t x=-3+4t y=-3+t y=4+t z=4-3t z=8-4t Then I found PQ and n and I am not sure what to do next to find the intersection point. Thank You |
| May6-12, 05:40 PM | #2 |
|
|
For example x - 2/2 = x - 1, but that's clearly not what you mean. The very first step in any math problem is to make sure you remove any ambiguity from your notation. That will help you avoid trivial mistakes. |
| New Reply |
| Tags |
| distance, intersection, linear algebra, lines, parametric |
Similar discussions for: Linear Algebra- Finding the intersection of two straight lines.
|
||||
| Thread | Forum | Replies | ||
| finding the intersection points of the two lines in space | General Math | 3 | ||
| Linear algebra - dimension and intersection | Calculus & Beyond Homework | 4 | ||
| Linear algebra, point of intersection | Calculus & Beyond Homework | 10 | ||
| Finding the point of intersection of two lines | Precalculus Mathematics Homework | 4 | ||
| Transformations taking straight lines to straight lines | Differential Geometry | 5 | ||