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Motion of a particle given position vector. |
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| May6-12, 04:58 PM | #1 |
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Motion of a particle given position vector.
1. The problem statement, all variables and given/known data
A position vector of a particle at a time t is r=icost +jsint +kt ; show the speed and the magnitude of the acceleration is constant. Describe the motion. 2. Relevant equations v = dr/dt a = dv/dt 3. The attempt at a solution Could someone let me know if I am doing this correctly? I derived the position to find the velocity: v = dr/dt = -isint +jcost + 1k Then derived the velocity : a = dv/dt = -icost -jsint Then found the magnitude of the acceleration: mag(a) = sqrt ( cos^2(t) + sin^2(t)) = 1 , which is constant. Motion- increasing oscillation? How would I show this? Thanks! |
| May6-12, 05:40 PM | #2 |
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Don't forget to find the speed (magnitude of the velocity).
Think about just the two-dimensional [itex]x,y[/itex] motion. What kind of motion would that be? Then notice that the [itex]z[/itex] component just linearly increases in one direction. What kind of shape will be created this way? And how will your particle move along that three dimensional shape? |
| May6-12, 05:48 PM | #3 |
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Would the particle just be moving around a circle? How could I prove this? Thanks! |
| May6-12, 06:03 PM | #4 |
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Motion of a particle given position vector.
Well, yes for the two-dimensional case it would be circular motion. If you don't recognize the form, try picking various values of [itex]t[/itex] and plotting them on a two dimensional graph to see it.
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| May6-12, 06:46 PM | #5 |
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Is it supposed to look like a spring? And was I correct about the velocity?
Thank you for the help. |
| May6-12, 07:09 PM | #6 |
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Exactly, it's the shape of a helix. The motion is circular, but it's traveling upwards along the surface of a cylinder with time.
And yes, you were right about the speed. |
| May6-12, 07:10 PM | #7 |
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Awesome! Thanks!
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| motion, particle, vector |
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