Rational and Irrational Numbers

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Homework Help Overview

The discussion revolves around proving that the sum of a rational number and an irrational number is irrational. Participants are exploring proof techniques, particularly proof by contradiction, and examining related questions about the sum of two irrational numbers.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to construct a proof by contradiction, starting with the assumption that the sum of a rational and an irrational number is rational. They discuss expressing the rational number in fractional form and manipulating the equation to reach a contradiction.

Discussion Status

There are multiple attempts to clarify the proof structure, with some participants suggesting alternative approaches and questioning the validity of the assumptions. The discussion includes considerations of related proofs, such as the sum of two irrational numbers, with some skepticism about generalizing the results.

Contextual Notes

One participant notes that the topic may not be directly related to physics, indicating a potential mismatch with the forum's focus. Additionally, there are mentions of counterexamples that challenge the assumption regarding the sum of two irrational numbers.

lokisapocalypse
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I need to show that a rational + irrational number is irrational. I am trying to do a proof by contradiction.

So far I have:

Suppose a rational, b irrational.
Then a = p/q for p, q in Z.
Then a + b = p/q + b = (p + qb) / q
But I don't know where to go from here because I still have a rational plus an irrational and that is what I am trying to show.

Also, would a similar proof work to show that an irrational + irrational = irrational?
 
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lokisapocalypse said:
I need to show that a rational + irrational number is irrational. I am trying to do a proof by contradiction.

So far I have:

Suppose a rational, b irrational.
Then a = p/q for p, q in Z.
Then a + b = p/q + b = (p + qb) / q
But I don't know where to go from here because I still have a rational plus an irrational and that is what I am trying to show.

When you're doing a contradiction, you should assume the opposite of the premise and show that it leads to an absurd conclusion.

For this problem, try this :

Let [itex]a = \frac{p}{q}[/itex] where p and q are coprime integers.

b is irrational.

Now let us say their sum is a rational number, which can be expressed as [itex]\frac{s}{t}[/tex], where s and t are coprime integers.<br /> <br /> Then,<br /> <br /> [tex]a + b = \frac{s}{t}[/tex]<br /> <br /> [tex]b = \frac{s}{t} - a = \frac{s}{t} - \frac{p}{q} = \frac{sq - pt}{qt}[/tex]<br /> <br /> We have just shown that b can be expressed as the ratio of two integers. But b is irrational.<br /> <br /> This is a contradiction. Hence the assumption is false and the original premise is true.<br /> <br /> <blockquote data-attributes="" data-quote="" data-source="" class="bbCodeBlock bbCodeBlock--expandable bbCodeBlock--quote js-expandWatch"> <div class="bbCodeBlock-content"> <div class="bbCodeBlock-expandContent js-expandContent "> Also, would a similar proof work to show that an irrational + irrational = irrational? </div> </div> </blockquote><br /> This isn't even true in general. What can you say about the sum of [tex]\sqrt{2}[/tex] and [tex](5 - \sqrt{2})[/tex] ?[/itex]
 
I need to show that a rational + irrational number is irrational. I am trying to do a proof by contradiction.

The proof is one line. :smile:

So, you're doing proof by contradiction, and have assumed that there are rational numbers p and q, and an irrational number z, such that:

p + z = q

right?


Also, would a similar proof work to show that an irrational + irrational = irrational?

It is also fairly easy to construct counterexamples... but the method might be easier to find once you've done the first problem.
 
I need to show that a rational - irrational number is irrational. I am trying to do a proof by contradiction.
Plz send me the related answer as I need it...
 
Last edited:
Since this clearly has nothing to do with physics, I am moving it to "precalculus homework".
 
Anjuyogi, take a look at the previous posts?
 

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