3 + 2 log (base 2) X = log (base 2) y

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Discussion Overview

The discussion revolves around the equation 3 + 2 log (base 2) X = log (base 2) y, specifically exploring how to manipulate this equation to show that y = 8X squared. The scope includes mathematical reasoning and problem-solving related to logarithmic properties.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant asks for help in demonstrating that y = 8X squared from the given logarithmic equation.
  • Another participant suggests rewriting the equation using properties of exponents and logarithms to derive the result.
  • A third participant expresses understanding after receiving guidance, indicating that the solution was not as difficult as initially thought.
  • Several participants inquire about the method used to write numbers as powers, indicating interest in the formatting of mathematical expressions.

Areas of Agreement / Disagreement

The discussion does not present any significant disagreement, but it remains focused on the problem-solving process rather than reaching a consensus on a final answer.

Contextual Notes

Participants have not explicitly stated all assumptions or provided detailed steps in their reasoning, which may affect the clarity of the derivation process.

Who May Find This Useful

Individuals interested in logarithmic equations, mathematical problem-solving, or those looking to understand the manipulation of logarithmic identities may find this discussion beneficial.

Gughanath
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3 + 2 log (base 2) X = log (base 2) y

how can this show, that y = 8X squared? Please help! :confused:
 
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Rewrite this equality as follows:
[tex]2^{(3+2log_{2}x)}=2^{log_{2}y}[/tex]

Now, use properties of exponents and logarithms to derive the result!
 
oh...I SEE...thanx...wasnt that hard :s
 
how did u write the numbers (powers) above the normal number btw?
 
Gughanath said:
how did u write the numbers (powers) above the normal number btw?
Click on the image to see the LATEX code behind it.
 

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