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Charge in conductors |
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| Aug13-12, 07:01 AM | #1 |
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Charge in conductors
1. The problem statement, all variables and given/known data
A sphere conductor of radius 18 cm has potential 27 Volt. Another sphere conductor has potential 18 Volt. Both of them are connected and the combined potential is 24 Volt. Find: a. the charge of second sphere b. the charge of each sphere now 2. Relevant equations Q = CV V = kQ / r 3. The attempt at a solution a. V1 = k.Q1 / r1 27 = 9 x 109 x Q1 / (18 x 10-2) Q1 = 5.4 x 10-10 C Then I don't know how to continue.....
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| Aug13-12, 07:09 AM | #2 |
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Try using conservation of charge.
EDIT: Are those two sphere of same radius? |
| Aug13-12, 07:52 AM | #3 |
Recognitions:
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You can calculate also the final charge Q1' on the first sphere, as its potential is known.
As for the second sphere, kQ2/R2=18 and kQ'2/R2=24. From here, you can find the ratio Q2'/Q2. As AGNuke said, the sum of the charge on the spheres is conserved: Q1+Q2=Q1'+Q2'. ehild |
| Aug13-12, 11:22 PM | #4 |
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Charge in conductors24 = 9 x 109 x Q1' / (18 x 10-2) Q1' = 4.8 x 10-10 C kQ2/R2=18 ; kQ'2/R2=24 So Q2'/Q2 = 24/18 = 4/3 Q1+Q2=Q1'+Q2' 5.4 x 10-10 + Q2 = 4.8 x 10-10 + 4/3 Q2 Q2 = 1.8 x 10-10 C Q2' = 2.4 x 10-10 C If the spheres have same radius, then the combined potential should be: (27 + 18)/2 = 45/2 V. Am I correct in this case? Thanks |
| Aug13-12, 11:37 PM | #5 |
Recognitions:
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ehild |
| Aug14-12, 04:26 AM | #6 |
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OK. Thanks a lot
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