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Blackbody Heat Shields/Metal Sheets |
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| Sep21-12, 03:28 AM | #1 |
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Blackbody Heat Shields/Metal Sheets
A “blackbody heat shield” is used to reduce radiant heat loss in situations where standard low conductivity insulation (i.e. normal insulation) cannot be used. The shield is constructed using a set of parallel metal sheets, each with emissivity 1.0.
Explain how/why this “heat shield” works and determine how many sheets of metal are required to reduce the heat loss to less than 20% of the unshielded value. (Hint: think about the radiation absorbed by each sheet and how this energy will be re-radiated.) Diagram: ![]() I really need help with this xD I don't even know where to begin. |
| Sep21-12, 07:36 AM | #2 |
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Here are some ideas:
- assume that the whole problem is 1-dimensional - begin with 1 heat shield: Where does it receive/emit radiation? - assuming that the environment has a temperature of ~0, calculate the temperature of that heat shield in equilibrium |
| Sep21-12, 09:33 AM | #3 |
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ummmm I still don't get it xD
do I use the equation: Q = mC deltaT? |
| Sep21-12, 09:46 AM | #4 |
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Mentor
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Blackbody Heat Shields/Metal Sheets
No, that looks like regular conduction.
##P_{emitted}=\sigma A T^4## (Stefan-Boltzmann) |
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| heat shield, radiant, thermal |
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