Flow Fully Dev: Find Length of Pipe for Velocity v

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SUMMARY

The discussion focuses on calculating the length of a pipe required for fully developed flow at different velocities using Reynolds number. For a velocity of 0.1 m/s, the Reynolds number is calculated as 2000, indicating laminar flow, leading to a length of 2.4 meters. At a velocity of 10 m/s, the Reynolds number is 200,000, indicating turbulent flow, resulting in a length of 0.673 meters. The concept of fully developed flow is clarified as a condition where the velocity distribution remains constant over time.

PREREQUISITES
  • Understanding of Reynolds number calculation
  • Knowledge of fluid dynamics principles
  • Familiarity with laminar and turbulent flow characteristics
  • Basic proficiency in dimensional analysis and unit conversion
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  • Study the implications of fully developed flow in pipe systems
  • Learn about the Darcy-Weisbach equation for head loss in pipes
  • Explore the differences between laminar and turbulent flow in detail
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Engineers, fluid mechanics students, and professionals involved in pipeline design and analysis will benefit from this discussion.

pyroknife
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I have attached the problem.

I did the problem, but I'm not confident about my approach or solution. The "fully developed" part is confusing me a little, but anways here'smy approach:

For v=0.1 m/s
Reynold's number=(density)*(velocity)*diameter/viscosity
=1000*.1*0.02/(10^-3)=2000 <<<< I think this indicates that its laminar?
If so then:
L/d=.06*Reynold's
L=.02*.06*2000=2.4m

For v=10m/s
Reynold's=200,000 <<< I think this indicates that its turbulent
If so then:
L/d=4.4(Reynold's)^(1/6)
L=.02*4.4*(200000^(1/6))
=.673m
 
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pyroknife said:
I have attached the problem.

I did the problem, but I'm not confident about my approach or solution. The "fully developed" part is confusing me a little, but anways here'smy approach:

For v=0.1 m/s
Reynold's number=(density)*(velocity)*diameter/viscosity
=1000*.1*0.02/(10^-3)=2000 <<<< I think this indicates that its laminar?
If so then:
L/d=.06*Reynold's
L=.02*.06*2000=2.4m

For v=10m/s
Reynold's=200,000 <<< I think this indicates that its turbulent
If so then:
L/d=4.4(Reynold's)^(1/6)
L=.02*4.4*(200000^(1/6))
=.673m

Let me guess. You are trying to calculate the nominal entry length for flow in a tube. You
used the correct equations, and implemented them correctly (assuming you got the units right).

Fully developed flow means that the velocity distribution is not changing with time.
 

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