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What does this boundary condition mean?

by HasuChObe
Tags: boundary, condition
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HasuChObe
#1
Oct30-12, 10:39 PM
P: 32
One of the boundary conditions for a homogeneous uniform waveguide is [tex]\frac{\partial H_z}{\partial n}=0[/tex]. What does this mean physically?
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Meir Achuz
#2
Nov2-12, 08:51 PM
Sci Advisor
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PF Gold
P: 2,010
I tried to put it into words, but the equation is clearer.
d/dn means the derivative in the direction perpendicular to the wall.
Aguss
#3
Mar1-13, 05:03 PM
P: 7
Hello!! I have a question related to this. This boundary condition yield from n.B = 0 , but i dont know how, from considering a cylindrical waveguide. I know that there is an equation (first of 8.24 from Jackson) but i dont realice how to use it. If u know, please let me know. Thankss

Meir Achuz
#4
Mar2-13, 04:09 PM
Sci Advisor
HW Helper
PF Gold
P: 2,010
What does this boundary condition mean?

You must mean Eq. (8.30): [tex]\partial_n(B_z)=0[/tex] at the surface.
It follows from (8.24) by dotting it with n. The two terms on the LHS are zero, giving the BC on B_z. Then, it follows That [tex]H_z(x,y)\sim\cos(m\pi x/A)\cos(n\pi y/B)[/tex]
for an AXB rectangular guide.
Aguss
#5
Mar3-13, 06:45 PM
P: 7
Thank you so much!


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