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A question about gravimetric analysis

Hello, I have been studying undergraduate level chemistry courses for PhD proficiency exam, and I have very recently been started Analytical Chemistry.

I have a simple problem and I solved it in a different way, could you please show me how I can solve it by using the known "gravimetric factor"? Or I maybe have used it without noticing

The question is as follows:

 An organic sample, weighing 0.2795 grams and known to include $\displaystyle C_6H_6Cl_6~(290.83~g/mol)$ and $\displaystyle C_{14}H_9Cl_5~(354.49~g/mol)$, is ignited with oxygen gas in a quartz tube, and products obtained (CO2, H2, and HCl) are passed from a NaHCO3 solution. After acidification, the total chloride ions are found to precipitate 0.7161 grams of AgCl (143.22 g/mol). Calculate the halogen percentage of each chlorinated organic compounds.
Okay, my solution goes like this:

 290.83x+354.49y=0.2795 g 6*35.5x+5*35.5y=0.005*35.5 g (0.005 is the number of moles of AgCl) from there, rearrangement gives the following: 290.83x+354.49y=0.2795 g -425.388x-354.49y=-0.35448 g adding and dividing reveals that x=0.00055723 and from the second (or first) equation, y is found to be 0.0003313. The gram equivalents of these x and y are 0.1620592 grams and 0.11744254 grams, respectively. Their percentages are 57.98% and 42.02%, respectively. The textbook says that the correct answers are 57.80% and 42.20%, resp.
My questions:

1) What is the cause I am getting different answers? I am suspecting from using 35.5 grams/mol for chlorine atom; maybe I have to find more precise number from elsewhere; it is not given to me in this question.

2) Can you please show the solution of this problem by using gravimetric factor, along with its description? I have been unable to comprehend it so far.

Thank you for your interest.
 Recognitions: Homework Help Science Advisor I'm not too familiar with this version of gravimetric analysis. Your answer does not seem too far off from the text's, so I'm not quite sure...perhaps the small deviation is because you neglected to use the stoichiometric ratio of molecule/chlorine. In the first organic compound it seems to be 1/6 and the second 1/5. Thus you're second equation may need to appear as 6*35.5(6moles/1mole)x+5*35.5(5moles/1mole)y=0.005*35.5 g (0.005 is the number of moles of AgCl).
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