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snells law

 
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Mar16-05, 06:24 PM   #1
 

snells law


so my given is 1.52 20degrees = 1.10 sin r

im trying to find sin r which comes out to 18.9 degrees but im not sure how find that, can somebody help me out please?

so you do 1.10/1.52

do you divide that into sin 20?
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Mar16-05, 06:36 PM   #2
 
I don't quite understand your notation....

Is that first part : 1.52 * 20 deg?
Mar16-05, 06:39 PM   #3
 
snells law is n1 sin i = n2 sin r

n1= 1.52
sin i = 20 deg

n2 = 1.10

sin r = ?

sin r actually equals 28.2 deg but i don't understand the process
Mar16-05, 06:42 PM   #4
 

snells law


Isn't this just simple algebra? What do you get when you solve for the unknown variable?
Mar16-05, 06:43 PM   #5
 
I got 27.6 as my answer...
Mar16-05, 06:43 PM   #6
 
.........

[tex]\sin{x}[/tex] does not give you an answer in degrees.

[tex]n_1 \sin{\theta_1} = n_2 \sin{\theta_2} \Longrightarrow \theta_1 = \sin^{-1}\left( \frac{n_2}{n_1} \sin{\theta_2}\right)[/tex]
Mar16-05, 06:45 PM   #7
 
Isn't the question what is sin r? Not what is the angle...
Mar16-05, 06:46 PM   #8
 
Well, in that case he's in for a surprise if he wants it to "come out to [tex]18.9^\circ[/tex]"
Mar16-05, 06:47 PM   #9
 
but how do you do it

1.10/1.52 =.723

sin 20=.723

then im stuck....
Mar16-05, 06:48 PM   #10
 
Look for the [tex] \sin^{-1}[/tex] button on your calculator. Apply it as in the equation I put above.
Mar17-05, 10:31 AM   #11
 
first calculate sin(20)
then multiply that by 1.52
then divide by 1.10
then take the arcsin/inverse sin of that number
make sure its in degrees and yorue done.

28.2
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