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snells law |
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| Mar16-05, 06:24 PM | #1 |
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snells law
so my given is 1.52 20degrees = 1.10 sin r
im trying to find sin r which comes out to 18.9 degrees but im not sure how find that, can somebody help me out please? so you do 1.10/1.52 do you divide that into sin 20? |
| Mar16-05, 06:36 PM | #2 |
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I don't quite understand your notation....
Is that first part : 1.52 * 20 deg? |
| Mar16-05, 06:39 PM | #3 |
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snells law is n1 sin i = n2 sin r
n1= 1.52 sin i = 20 deg n2 = 1.10 sin r = ? sin r actually equals 28.2 deg but i don't understand the process |
| Mar16-05, 06:42 PM | #4 |
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snells law
Isn't this just simple algebra? What do you get when you solve for the unknown variable?
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| Mar16-05, 06:43 PM | #5 |
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I got 27.6 as my answer...
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| Mar16-05, 06:43 PM | #6 |
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.........
[tex]\sin{x}[/tex] does not give you an answer in degrees. [tex]n_1 \sin{\theta_1} = n_2 \sin{\theta_2} \Longrightarrow \theta_1 = \sin^{-1}\left( \frac{n_2}{n_1} \sin{\theta_2}\right)[/tex] |
| Mar16-05, 06:45 PM | #7 |
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Isn't the question what is sin r? Not what is the angle...
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| Mar16-05, 06:46 PM | #8 |
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Well, in that case he's in for a surprise if he wants it to "come out to [tex]18.9^\circ[/tex]"
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| Mar16-05, 06:47 PM | #9 |
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but how do you do it
1.10/1.52 =.723 sin 20=.723 then im stuck.... |
| Mar16-05, 06:48 PM | #10 |
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Look for the [tex] \sin^{-1}[/tex] button on your calculator. Apply it as in the equation I put above.
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| Mar17-05, 10:31 AM | #11 |
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first calculate sin(20)
then multiply that by 1.52 then divide by 1.10 then take the arcsin/inverse sin of that number make sure its in degrees and yorue done. 28.2 |
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