How Do I Calculate the Magnetic Force on a Coil from a Circular Ring?

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SUMMARY

The discussion focuses on calculating the magnetic force on a coil positioned along the axis of a circular ring carrying a current. The derived formula for the force, F, is given as F = -\frac{\mu_0 II'nSa^2}{2} ((a^2 + (\frac{l}{2} - d)^2)^\frac{-3}{2} - (a^2 + (\frac{l}{2} + d)^2)^\frac{-3}{2}). The key approach involves using the integral F=\int I(dl\times B), where B represents the magnetic field generated by the ring. Participants emphasize the importance of understanding the integration process to arrive at the final expression for force.

PREREQUISITES
  • Understanding of magnetic fields and forces, particularly Ampère's Law.
  • Familiarity with the Biot-Savart Law for calculating magnetic fields from current-carrying conductors.
  • Knowledge of calculus, specifically integration techniques.
  • Concept of magnetic permeability, denoted as μ₀.
NEXT STEPS
  • Study the Biot-Savart Law to understand how to calculate magnetic fields from current distributions.
  • Learn about Ampère's Law and its applications in magnetic field calculations.
  • Practice integration techniques relevant to physics problems, focusing on vector calculus.
  • Explore the concept of magnetic permeability and its role in electromagnetic theory.
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Students and professionals in physics, electrical engineering, and anyone involved in electromagnetic theory or applications of magnetic forces in coils and circuits.

meteorologist1
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I'm stuck on the following problem:

A long thin coil of length l, cross-sectional area S, and n turns per unit length carries a current I. It is placed along the axis of a large circular ring of radius a, which is carrying a current I'. If d is the displacement of the center of the coil from the center of the ring along the coil axis, find the force on the coil as a function of d.

I'm not sure what formulas to use, and what I have to integrate to get the following result:
[tex]F = -\frac{\mu_0 II'nSa^2}{2} ((a^2 + (\frac{l}{2} - d)^2)^\frac{-3}{2} - (a^2 + (\frac{l}{2} + d)^2)^\frac{-3}{2})[/tex]

Thanks.
 
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Hello,first post ever, you could try to use the force from the formula

[itex]F=\int I(dl\times B)[/itex]

Where B is the field from the ring
 
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