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calculating area |
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| Apr12-05, 06:25 PM | #1 |
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calculating area
Im a first year electrical apprentice and I cant work out the area for resistance. The formula is R = PL/A :eg 20mm by 9mm conductor the answer has to be in meters squared can you show me the formula please?
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| Apr12-05, 06:26 PM | #2 |
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Is that a rectangle,or an ellipse???I think you mean
[tex] R=\rho\frac{l}{S} [/tex] Daniel. |
| Apr12-05, 06:27 PM | #3 |
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Are you just asking how to find out how many meters-squared an area 20 mm by 9 mm is?
If so, just convert each length into meters (0.020 m x 0.009 m) and multiply them. - Warren |
| Apr13-05, 06:22 AM | #4 |
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calculating area
A question I have for homework is find the resistance of a 500 meter length of copper conductor having a cross sectional area of 20mm by 9mm? I know the resistivity of copper is 1.72 x10-8 and L is given 500, the A I think is 1.8x10-4. So R=PL/A !.72x10-8 x 500 / 1.8x10-4. The answer I get is 4.7 but the answer I'm supposed to get is 0.133 . Can you tell mr where Ive gone wrong?
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| Apr13-05, 08:58 AM | #5 |
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Again,check your arithmetics.The surface is okay.
Daniel. |
| Apr13-05, 09:36 AM | #6 |
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I get 0.0477 ohms (this number is also within 10% of a number generated from the american wire gauge tables, so I believe it is correct).
Are you sure you have written down the dimensions correctly ? |
| Apr14-05, 03:31 AM | #7 |
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The actual question is. A copper conductor is 200 meters long and has a rectangular cross section of 12mm by 8mm. It's resistance is 0.01 ohm. Find the resistance of 500 meters of a copper conductor having a cross section of 20mm by 9mm?
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| Apr14-05, 10:40 AM | #8 |
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That's something else.
[tex] R=\rho\frac{l}{S} [/tex] Use this for the first conductor to find [itex] \rho [/itex] and then use this resistivity to find the resistance of the 2-nd conductor. Daniel. |
| Apr16-05, 07:42 PM | #9 |
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I did try that Daniel but I still cant arrive at the answer the course notes gives . I think my calculations for area isn't right. Is 20mm by 9mm 20+9=29 x 10-3squared =2.9x10-5 or is it 20x9=180x10-3squared 1.8x10-4. Or is there another way?
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| Apr16-05, 10:04 PM | #10 |
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[tex] 20 \mbox{mm}\cdot 9 \mbox{mm}=180 (\mbox{mm})^{2}=1.8\cdot 10^{-4}\mbox{m}^{2} [/tex]
That's the area. Daniel. |
| Apr16-05, 10:16 PM | #11 |
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Thanks mate!
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