# If someone can tell me about light...

by Tsunami
Tags: light
 Mentor P: 28,804 You posted in the wrong section. You want the Homework help section. Instead, you went into Academic and Career advise sectioin. Zz.
 P: 15,325 Are you looking for a quantitative (formulaic) answer, or merely a conceptual understanding of why it is so?
P: 92

## If someone can tell me about light...

Usually, if someone passes me the formula, then I can figure out why it is so as well.

But if you can give me either, that would be great.

Zapper : I wasn't sure, since my question is of academic level... I'm always confused when it comes to comparing foreign systems of education (I assumed college level was something like what we call 'secondary school').

Maybe a moderator can move this thread? Or can I do it myself?
 Emeritus Sci Advisor PF Gold P: 4,618 This forum is for career guidance, I will move it to homework as ZapperZ suggested.
 Sci Advisor HW Helper P: 1,769 I've read through your post rather quickly (due limited time) so the following may not apply draw a ray from the inner surface/lower end of the quarter circle straight up until it hits the outer surface. From this point draw a line toward the center of this circle, a radial line. Connect these two lines and you should have a triangle. Note that the radius is the normal for the incident ray. You should now able able to relate this incident angle to the critical angle so that you can obtain a relationship between the indices of refraction and the radius.
 Sci Advisor HW Helper P: 1,769 $$(R-d)/R=n_{out}/n_{in}$$
 P: 92 Thank you very much.

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