Joe's Uranium Problem: Alpha Particle Emission & Final Nucleus Mass

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SUMMARY

The discussion centers on the alpha decay of a 232/92 Uranium nucleus, which emits an alpha particle (4/2 He) with a kinetic energy of 5.32 MeV. The resulting nucleus is identified as 228/90 Thorium (Th). The kinetic energy of the emitted alpha particle is indeed the energy released during the reaction, which can be used to calculate the change in mass of the final atom. Joe seeks clarification on this process and the implications of the kinetic energy in relation to mass change.

PREREQUISITES
  • Understanding of nuclear decay processes, specifically alpha decay.
  • Familiarity with the concept of kinetic energy in nuclear reactions.
  • Knowledge of mass-energy equivalence (E=mc²).
  • Basic familiarity with atomic notation (e.g., isotopes, atomic numbers).
NEXT STEPS
  • Study the principles of alpha decay and its implications on nuclear stability.
  • Learn about mass-energy calculations in nuclear reactions using Einstein's equation.
  • Explore the concept of binding energy and its relation to nuclear decay.
  • Investigate the properties and applications of Thorium-228 in nuclear physics.
USEFUL FOR

Students of nuclear physics, researchers in atomic science, and anyone interested in the mechanics of radioactive decay and energy release in nuclear reactions.

josephcollins
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Here I have a problem:

A 232/92 Uranium nucleus emits an alpha particle with kinetic energy=5.32MeV. What is the final nucleus and what is the approximate mass(in units) of the final atom.

I can write the equation for the reaction, this will give 4/2 He and 228/90 Th. If the alpha particle has KE=5.32MeV then is this the energy emitted in the reaction? If this is then I can obtain the change in mass. Is this correct? Any help is welcomed, thx. Joe
 
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