Find Equation of Circle: A(2,2) & B(5,3), y=x+1

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SUMMARY

The equation of a circle can be determined using the points A(2,2) and B(5,3) along with the constraint that its center lies on the line defined by y=x+1. By substituting the points into the standard circle equation (x-p)² + (y-q)² = r², an equation involving the center coordinates (p, q) is derived, specifically 3p + 2q = 13. Given that the center lies on the line, the relationship q = p + 1 can be used to solve for the center and subsequently the radius of the circle.

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  • Understanding of the standard circle equation (x-p)² + (y-q)² = r²
  • Knowledge of coordinate geometry, specifically points and lines
  • Ability to solve linear equations
  • Familiarity with substitution methods in algebra
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  • Study the method of substitution in solving simultaneous equations
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how would you find the equation of a circle : (x-p)^2 + (y-q)^2=r^2 with this given info:

the circle passes through A(2,2) and B(5,3) and its centre is on the line defined by y=X+1
 
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Plug the two points in the equation and then you get an equation with p and q which should look like 3p+2q=13.

since the center is on the line y=x+1, and the center of the circle is supposed to be (p,q). So q=p+1.

then solve for the equation.
 

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