Rate of rotation and inertia (prevent homicide and help me, please)

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SUMMARY

The discussion centers on calculating the rate of rotation of a diver who changes her body position, impacting her moment of inertia and angular momentum. The diver initially rotates at 1 Hz in a stretched position, and when she tucks in, her length is halved. By applying the principle of conservation of angular momentum (L = Iω), it is established that as the moment of inertia (I) decreases, the angular velocity (ω) must increase to maintain constant angular momentum. The conclusion drawn is that the diver's rate of rotation increases to 4 Hz when she tucks in.

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NoHeart
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i understand 4 of the 6 problems on this week's online physics quiz, but this one is driving me completely NUTS!

a diver rotates at 1 revolution per second in the stretched out position. when the diver tucks her head in and bends her legs, assume her length is shortened by 1/2. what is her rate of rotation in this position?
my choices are 4 Hz or 5 Hz, you'd think having only 2 choices would make this easier, but alas, i am dumbfounded.

i have tried thinking of the diver in the stretched out position as a rod, with rotational inertia 1/12ML^2
the other position would be like a solid sphere, with rotational inertia 2/5MR^2

1 revolution per second is 1 Hz, or 2pi r/s

the angular momentum (which may be irrelevant) of the stretched out position is
L= 1/12M(2r)^2 * 6.28 radians/1 revolution * 1 revolution/1second
this leaves me with L=2.093Mr^2 rad/sec

L of ball position is
2/5Mr^2 * 6.28 radians/?sec= 2.51Mr^2 radians/?sec
?=0.39Mr^2 rad/sec

slowly going insane, i see that rotational acceleration = net torque/rotational inertia
this also leads me nowhere

any help, hints, or a slap across the face would be greatly appreciated

(p.s.- anyone else think online physics is the STUPIDEST idea EVER?)
 
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*Slaps NoHeart in the face*, "wake up man!"

Lol...just kidding. :-p

Keep in mind these quizzes never have super complex questions, they are always just testing the basic concepts. In this case, angular momentum, L, can be expressed as:

[tex]L = I\omega[/tex]

Where I is the moment of inertia. Keep it simple, model the diver as having the same overall shape, whether she's fully extended or not. After all, they only give you length, [itex]l[/itex], to work with. So if:

[tex]I \propto l^2[/tex]

then when [itex]l[/itex] is halved, by what factor does I decrease? _________

But if I decreases by that factor, and by conservation of angular momentum, the product [itex]L = I\omega[/itex] must remain constant, then by what factor does [itex]\omega[/itex] increase to compensate?

Yes, I also feel that online physics quizzes are a stupid idea.
 
1/4! i love you!
and i wish it were only the quizzes that are online, but it's the whole class- the online "lectures" are simply outlines of the chapters in the book, and the book is completely useless when it comes to the quizzes and tests. i have been teaching myself all of the concepts involved in the class so far, with the help of many physics sites and this here amazing message board. if i had found this board at the beginning of the quarter, i'd probably have an A instead of a B.
 

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