Help with Determining Planet Density from Orbital Period

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SUMMARY

The discussion focuses on calculating the density of a planet based on the orbital period of a satellite in a circular orbit near its surface. Given a period of 1.69 hours, the approach involves applying Kepler's Third Law of Planetary Motion and equating gravitational force with centripetal force. The key equations include the gravitational force formula, the relationship between velocity and angular frequency, and the density formula for a uniform sphere. By simplifying these equations, one can derive the planet's density.

PREREQUISITES
  • Understanding of Kepler's Third Law of Planetary Motion
  • Familiarity with gravitational force and centripetal force equations
  • Basic knowledge of angular frequency and its relationship to orbital motion
  • Concept of density for uniform spherical objects
NEXT STEPS
  • Study the derivation of Kepler's Third Law in detail
  • Learn how to apply gravitational force equations in orbital mechanics
  • Explore the concept of angular frequency and its applications in physics
  • Investigate the calculation of density for various celestial bodies
USEFUL FOR

Astronomers, physicists, students studying orbital mechanics, and anyone interested in calculating planetary densities based on satellite motion.

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I have no idea where to start on this:

A satellite is in a circular orbit very close to the surface of a spherical planet. The period of the orbit is 1.69 hours.
What is density of the planet? Assume that the planet has a uniform density.

Perhaps someone could point me in the right direction? Thanks.
 
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ninjagowoowoo said:
I have no idea where to start on this:

A satellite is in a circular orbit very close to the surface of a spherical planet. The period of the orbit is 1.69 hours.
What is density of the planet? Assume that the planet has a uniform density.

Perhaps someone could point me in the right direction? Thanks.

Let the mass of the planet be M, the mass of the satellite be m, the radius of the planet be R, and all the other symbols have their usual meanings.

1. You should know that the centripetal force causing the satellite to be in the circular orbit is due to the gravitational force, so equate the two, i.e.

[tex]\frac{GmM}{R^2} = \frac{mv^2}{R}[/tex]

2. But you also know that

[tex]v = r\omega[/tex]
[tex]\omega =2\pi/T[/tex]
[tex]\rho = \frac{M}{4/3 \pi R^3}[/tex]

3. A bunch of things cancel out and you should be able to do the simple algebra to find the density.

Zz.
 
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