Period for electromagnetic waves

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Homework Help Overview

The discussion revolves around understanding the relationship between the period and wavelength of electromagnetic waves, specifically X-rays and other forms of electromagnetic radiation. The original poster seeks clarification on how to approach problems involving wave speed, frequency, and the effects of different media on wavelength.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to clarify the relationship between period and frequency, questioning if they are equivalent. They also inquire about the appropriate equations to use for calculating wavelength in different media.

Discussion Status

Participants have provided explanations regarding the definitions of period and frequency, as well as the speed of light in various media. There is an ongoing exploration of unit analysis as a method to understand the relationships between the variables involved. Multiple interpretations of the problems are being discussed, but no consensus has been reached.

Contextual Notes

The original poster expresses difficulty in finding relevant information in their textbook regarding wavelengths and periods, indicating a potential gap in their resources. They emphasize a desire to understand the concepts rather than simply obtain answers.

convict11
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Hi, I have a couple of questions here I am having a little bit of difficulty with.

1) What is the wavelength of an X-ray that has a period of 1.30x10e-10s?

2) A certian EMR has a wavelength of 2.14x10e-5m in air. What is the wavelength is water(n = 1.33)?

I am not looking for the answers as I prefer to be able to understand the questions and how the answers are correct but I have searched the the textbook on this unit about magnetic fields and electric fields but can not find anything of wavelengths and periods. If anyone could tell me the equation to use or anything it would be great

All I know is that Speed of wave = Frequency * Wavelength

Is the period the frequency? and the speed of wave would be the speed of light?
 
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convict11 said:
Is the period the frequency?
Almost. The frequency is how many oscillations the wave goes through in a second. The period is the time it takes the wave to complete one oscillation. A little proportionality relation shows that

[tex]\frac{f}{1s}=\frac{1}{T}[/tex]

where T is the period, and f the frequency.


convict11 said:
and the speed of wave would be the speed of light?
Yes, but the speed of light varies depending on the medium it travels in. You ought be have a formula relating speed of light of wavelength as a function of the refractive index n somewhere in your notes or book.
 
In order to understand some of the methods of solving the questions you asked, it is often very helpful to do a unit analysis on a piece of paper. If you know the units of certain variables (e.g. frequency, period, etc) it is often very simple to see the relationship. For instance, if you know the frequency is in the units [1/s] and that period is in the units , it's easy to see that there's an inverse relationship.

You noted that [itex]v=f\lambda[/itex]. If you do a unit analysis on that, you see that you will get [itex][m/s]=[1/s][m][/itex], an the units work out to equal each other. If you're ever stumped as to how an equaton should look, or which variables you might need to use, or you have a question along the lines of "is the period the frequency," a unit analysis can often provide a quick and easy answer.

In response to your second problem, you have an index of refraction n. n is defined as the ratio of the speed of light in vacuum to the speed of light in the medium in question. In this case, the speed of light in vacuum is 1.33 times faster than the speed of light in the medium. This essentially means that all of the waves will propagate at c/1.33 through the medium, and therefore the wavelengths will also be that much smaller. It's a simple multiplication/division factor on [itex]\lambda[/itex]
 
Thanks a lot

Thanks for the reply's guys
 

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