Young's Interference Exp: Min Distance b/w Bright Fringes 540nm & 450nm

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Homework Help Overview

The discussion revolves around a Young's interference experiment involving two wavelengths of light, 540 nm and 450 nm, and the calculation of the minimum distance from the center of the screen to the point where bright fringes from both wavelengths coincide. The setup includes slits separated by 0.132 mm and a screen located 1.47 m away.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of the formula for bright fringe locations and question how to find the point where fringes from both wavelengths overlap. There is an exploration of equating the two equations derived from the wavelengths to find a common distance.

Discussion Status

Participants are actively engaging with the problem, questioning the setup and exploring different approaches to find a solution. Some have expressed uncertainty about their methods and are seeking clarification on how to proceed with their calculations.

Contextual Notes

There is an emphasis on understanding the conditions necessary for the bright fringes to coincide, and participants are considering the implications of the wavelengths and their corresponding fringe orders in their calculations.

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In a Young's interference experiment, the two slits are separated by 0.132 mm, and the incident light includes light of wavelengths λ1 = 540 nm and λ2 = 450 nm. The overlapping interference patterns are formed on a screen 1.47 m from the slits. Calculate the minimum distance from the center of the screen to the point where a bright line of the λ1 light coincides with a bright line of the λ2 light.

I know the formula for the location of a bright fringe is:

Yb=m*lamda*L/d

so do i just calculate the distance of a bright fringe at the 540 wavelength and then the 450 wavelength and then just the distance b/w them is the answer to the question?
 
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DDS said:
In a Young's interference experiment, the two slits are separated by 0.132 mm, and the incident light includes light of wavelengths λ1 = 540 nm and λ2 = 450 nm. The overlapping interference patterns are formed on a screen 1.47 m from the slits. Calculate the minimum distance from the center of the screen to the point where a bright line of the λ1 light coincides with a bright line of the λ2 light.

I know the formula for the location of a bright fringe is:

Yb=m*lamda*L/d

so do i just calculate the distance of a bright fringe at the 540 wavelength and then the 450 wavelength and then just the distance b/w them is the answer to the question?

No. The question asks you for the location where both patterns have bright lines that coincide, i.e., happen in the same place. You have two equations for the two different wavelengths that must yield the same value for Y. How is that possible?
 
So do i set up each equation with there corresponding wavelength , equate them and find y?

What process do i need to undertake to get my asnwer
 
DDS said:
So do i set up each equation with there corresponding wavelength , equate them and find y?

What process do i need to undertake to get my asnwer

The process you need to undertake is for you to try to solve the problem the way you think it needs to be solved. You obviously have an idea how to do it. Follow your idea and see where it leads.
 
i followed it the way i think and it lead to the wrong asnwer that's why i am asking for help
 
DDS said:
i followed it the way i think and it lead to the wrong asnwer that's why i am asking for help

Show us what you did.
 
DDS said:
i followed it the way i think and it lead to the wrong asnwer that's why i am asking for help

Ok, what must be true to have both diffraction gratings to coincide with each other? Don't mind the distances yet...
 
its a ration between

m1/m2=lada2/lamda1

find the ratio plug it back into eitehr distance formula and bingo answer time
 

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