Calculate the linear acceleration of a car

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SUMMARY

The linear acceleration of a car with 0.300 m radius tires and an angular acceleration of 10 rad/s² is calculated to be 3.0 m/s². In 2.5 seconds, the tires make approximately 4.97 revolutions, starting from rest. The final angular velocity after this time is 25 rad/s, leading to a final linear velocity of 7.5 m/s for the car. The calculations confirm the accuracy of the results provided by the user Nautica.

PREREQUISITES
  • Understanding of linear and angular acceleration concepts
  • Familiarity with the relationship between linear velocity and angular velocity
  • Knowledge of kinematic equations for rotational motion
  • Basic proficiency in unit conversions between radians and revolutions
NEXT STEPS
  • Study the kinematic equations for rotational motion, specifically Δθ = ωo*t + 0.5*α*t²
  • Learn about the conversion between angular velocity (rad/s) and linear velocity (m/s)
  • Explore the implications of tire radius on vehicle acceleration and speed
  • Investigate the effects of slippage on tire performance and calculations
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Physics students, automotive engineers, and anyone interested in understanding vehicle dynamics and acceleration calculations.

nautica
a) Calculate the linear acceleration of a car, the 0.300 m radius tires of which have an angular acceleration of 10 rad/sec^2, assume no slippage.

a = ?
r = 0.30 m
Rot acc = 10.0 rad/s^2

a = r * (rotational acc)
a = .3 m * 10 rad/s^2
a = 3.0 m/s^2

b) How many revolutions do the tires make in 2.5 s if they start from a rest?

V final = 10 rad/s^2 * 2.5 s * 1 rev / 2pie rad = 3.98 rev/s

(Vf - Vo)/2 should give average velocity so

(3.98 rev/s)/2 = 1.98 rev/s

1.98 rev/s * 2.5 s = 4.97 rev

c) What is their final angular velocity?

W = Wo + (rotational acc) * time

W = 10 rad/s^2 = 25 rad/s

d) What is the final velocity of the car?

v = (.3m) * (25 rad/s) = 7.5 m/s

Could someone check this please - I feel relatively confident - but you will not hurt my feelings if you tell me I am wrong.

Thanks
Nautica
 
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Your answers are correct. You could have done part b in one step if you used Δθ = ωo*t + .5*α*t^2 and there was a typo in the third line of your solution to part c, but that's neither here nor there.
 
I see that now

Thanks
Nautica
 

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