Show me a derivation of the BKE

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Discussion Overview

The discussion centers around the derivation of the Basic Kinematic Equation (BKE) in the context of advanced dynamics. Participants explore the formulation and potential proofs of the equation, considering both formal and geometrical approaches.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant requests a formal derivation of the BKE, specifying the components involved such as inertial and working frames, angular velocity, and the cross product operator.
  • Another participant expresses willingness to provide a derivation but indicates that it may take considerable time to prepare.
  • A later reply mentions the discovery of a more geometrical proof of the BKE, though the participant lacks the means to share the proof for verification at the moment.

Areas of Agreement / Disagreement

Participants do not reach a consensus on a single derivation method, as multiple approaches are suggested, including formal and geometrical proofs. The discussion remains open-ended regarding the verification of these methods.

Contextual Notes

There are limitations in the discussion regarding the clarity of the derivations and the availability of resources to share proofs, such as scanning equipment. Additionally, the assumptions made about the linear velocity between frames are noted but not resolved.

Who May Find This Useful

This discussion may be useful for students and professionals in advanced dynamics, particularly those interested in kinematic equations and their derivations.

abercrombiems02
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For any of you advanced dynamics people, can you please show me a derivation of the BKE. (Basic Kinematic Equation)

The BKE is...

e d/dt(Vector) = u d/dt(Vector) + omega between e and u X (Vector)

sometimes an additional term is added which is the linear velocity between the frames but for some simplicity let's assume this is zero.

e is the inertial frame
and u is the working frame

omega is the angular velocity
X is the cross product operator

I know just by looking at a simple single rotation problem, the solution is trivial but does anyone know of a formal proof?
 
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I do, but I think it will take me a month of Sundays to write here. Let me see if I can scan in my old dynamics notes from school. Give me a bit!
 
Thanks, take your time, I'm in no rush!
 
Here we go. I had to scan it in from my Dynamics class notes. The pdf is a bit rough on the quality side. If you can't read it, let me know and I'll e-mail you the scan.
 
Last edited:
thanks a lot! This works perfectly. I actually found a more geometrical way to prove it with the few extra hours i had to spare today. Unfortunately, I don't have a scanner to show anyone to ensure correctness. Perhaps when I get back to school I can scan it in and have someone verify that my method is correct. Thanks again!
 

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