Find p in Parabola Problem with {x | -50 < x < 50}, {y | 0 < y < 20}

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SUMMARY

The discussion focuses on determining the value of p in the equation of a parabola given its vertex at (0, 20) and the constraints {x | -50 < x < 50}, {y | 0 < y < 20}. The parabola opens downward, and the equation can be expressed as (x - 0)² = 4p(y - 20). By substituting the point (50, 0) into this equation, participants can solve for p definitively.

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yourmom98
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Given {x | -50 < x < 50}, {y | 0 < y < 20} vertex at (0,20) it is a parabola find the equation in (x-h)^2=4p(y-k)

its pretty easy except how do i find p?
 
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The information you given isn't enough- I assume you mean a parabola with vertical line of symmetry, vertex at (0, 20), and such that when x=50, y= 0.
(From {x|-50< x< 50}, {y|0< y< 20}, my first guess was x= 50, y= 20 but then I saw that the vertex was at y= 20 so the parabola must be opening downward.)

Since you only ask about p, I assume you understand that since the vertex is at (0, 20), the equation is (x- 0)2= 4p(y- 20). Now, put x= 50, y= 0 in that and solve for p.
 

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