How Does Gauss' Theorem Transform Volume to Surface Integrals?

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SUMMARY

The discussion centers on the application of Gauss' Theorem, also known as the Divergence Theorem, which states that the volume integral of the divergence of a vector field J over a volume V is equal to the surface integral of J over the boundary surface S. The specific mathematical representation discussed is ∫(V) ∇·J dτ = ∮(S) J·dS. Participants clarify that Gauss' Law cannot be used to prove this theorem, as the Divergence Theorem is a more general principle that can indeed be used to derive Gauss' Law.

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dreamfly
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how -∫(v)laplace functor *J*dτ change into -∮(s) J(n) dS using Gauss formula?
 
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Do you mean

[tex]\int_V \vec \nabla \cdot \vec J d\tau = \oint_S \vec J \cdot d\vec S[/tex]
under the appropriate conditions on J, S and V.

This is the divergence theorem (also called Gauss' or Ostrogradsky's theorem). You cannot use Gauss' Law (if that is what you meant) to prove this. the divergence theorem is stronger and can be used to prove Gauss' law.
 
ok thanks! it's just our teacher told us to prove this equation by Gauss' theorem.and now I've known the process.thanks!
 

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