|Sep13-05, 08:31 PM||#1|
Hartree-Fock exchange operator
I'm trying to understand the Hartree-Fock mathematical formulation I understand the Coulomb operator, but I dont understand the exchange operator:
Can any one explain me why this operator is like this. I understand that it is the interaction of the j-th electron with the electrons' cloud but... how it come to be like that
thanks in advance
|Sep13-05, 09:46 PM||#2|
I don't know anything about that formulation, but this book on Google Print might help:
You can't see all the relevant information, but I think it might help you understand where the idea's headed.
|Sep26-05, 08:47 AM||#3|
I guess the integral on the rhs is simply the matrix element <j|K|phi> of the electrostatic potential. Therefore K|phi> is indeed given by |j><j|K|ph> .
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