Probability of Letters in Envelopes: A1, A2, A3, A4, A5

  • Thread starter Thread starter iNCREDiBLE
  • Start date Start date
  • Tags Tags
    Probability Work
Click For Summary
SUMMARY

The discussion focuses on the probability calculations related to letters being placed in envelopes by Mr. X's son. The probabilities for various scenarios are established: A1 receiving his letter has a probability of 1/5, while both A1 and A2 receiving their letters together has a probability of 1/20. The probability of A1 receiving his letter while A2 does not is calculated as 3/20. Additionally, the probability that at least one of A1, A2, or A3 receives their letter is determined to be 3/5, while the probability that no one receives their letter is confirmed to be 1/5.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with combinatorial mathematics
  • Knowledge of factorial notation
  • Ability to calculate probabilities for independent events
NEXT STEPS
  • Study the principles of combinatorial probability
  • Learn about independent and dependent events in probability theory
  • Explore advanced probability topics such as conditional probability
  • Practice problems involving permutations and combinations
USEFUL FOR

Students of mathematics, educators teaching probability, and anyone interested in understanding basic probability calculations in real-world scenarios.

iNCREDiBLE
Messages
128
Reaction score
0
Scenario: Mr. X is writing letters to five persons A1, A2, A3, A4, A5. After Mr. X has written them he has to leave the room where the letters and envelopes are. Mr X's son, who can't read, decides to help his dad and puts each letter in different envelopes. What is the probability that:

a) A1 gets his letter
P = 1/5.

b) A1 and A2 both gets their letters
P = (1/5)(1/4) = 1/20.

c) A1 gets his letter and A2 doesn't get his
P = (1/5)(3/4) = 3/20.

d) at least one of A1, A2, A3 gets his/their letter
Need help with this one.
P = 1 - (4/5)(3/4)(2/3) = 1 - 2/5 = 3/5 ?

e) no one gets their letter
P = 4!/5! = 1/5.
 
Last edited:
Physics news on Phys.org
You nailed em. Congrats.

Carl
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 57 ·
2
Replies
57
Views
7K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K