Interpreting Velocity Components in a Non-Head On Collision

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SUMMARY

The discussion focuses on interpreting the velocity components of two equal mass balls during a non-head-on collision. The initial vertical momentum is zero, leading to the conclusion that the vector sum of the final vertical components must also equal zero. Consequently, the y-components of the velocities of both balls must be equal in magnitude but opposite in direction to ensure momentum conservation. The discussion emphasizes the importance of understanding vector components in collision scenarios.

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  • Understanding of momentum conservation principles
  • Familiarity with vector components in physics
  • Knowledge of basic collision types and their characteristics
  • Ability to interpret and analyze collision problems
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  • Study the principles of elastic and inelastic collisions
  • Learn about vector decomposition in physics
  • Explore momentum conservation in two-dimensional collisions
  • Review examples of collision problems involving equal mass objects
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators seeking to clarify concepts related to momentum and vector analysis in collisions.

twofish
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Hi all,
I'm new here and am having a problem interpreting a homework question, hope i can explain it correctly.
The question is below.

"One ball goes along the x-axis and collides with a stationary ball of equal mass in a collision that is not head on. How does the y component of each velocity compare afterwards? Give both magnitude and direction."

My answer thus far is;
"When ball A is rolling along the x-axis there is no initial vertical momentum or y component, therefore the vector sum of the final vertical (Y) components of the two balls must be zero. "

What's got me hung up is the magnitude and direction part of the question.
Since I'm not really given any numbers to work with I'm unsure how to answer the second part of the question.
Can I assume that they are looking for the magnitude of the velocity, in which case I would answer v`a = (p`a)/(ma) for ball a, and similar for ball b.
Or do they want the magnitude of the vectors, in which case I would have to incorporate cos θ = (p`a)/p` and sin θ = (p`b)/p`
Thanks,
 
Last edited:
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You're absolutely right that the y-component of the momentum must be zero. Now - you have two balls of equal mass. What can you say about the y-component of their velocities (both the magnitude and the direction) if the y-momentum is to cancel out? Note: You won't be able to give a numeric answer for the speeds, but you can say how they compare. Hint hint.
 
Last edited:
Hrm ..okie, well I'll try working that angle.
Thanks much!
 

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