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Old Oct4-05, 07:28 PM                  #1
erik-the-red

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Confused on conservation of momentum?
Somebody throws me a ball with mass .400 LaTeX Code: kg at velocity 10.0 LaTeX Code: m/s . My mass is 65.5 LaTeX Code: kg .

1. If I catch the ball, with what speed do the ball and I move afterwards?

Shouldn't the answer be LaTeX Code: (.400)(10.0=(65.9)(v_2) , where LaTeX Code: v_2=.0607 LaTeX Code: m/s ?
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Old Oct4-05, 07:39 PM                  #2
Doc Al

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That's correct. (Assuming no other forces act on you.)
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