
#1
Oct605, 09:26 PM

P: 16

Please help me solve this problem.
Find numbers a, b, and c so that the graph of f(x) = ax^2 + bx + c has xintercepts at (0,0) and (8,0) and a tangent with slope 16 where x = 2. I have done this so far: f(x) = ax^2 + bx + c f '(x) = (2)(a)(x) + b 16 = (2)(a)(2) + b 16 = 4a + b I don't know where to go from here, so any help would be greatly appreciated. 



#2
Oct605, 09:30 PM

P: 16

Nevermind, I solved it. If anyone else needs the solution to this problem, let me know. :)



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